Relativistic addition of velocities in a five-dimensional spacetime
Abstract
Content:
1. Introduction
2. The rotation angle
3. Proof of the procedure
4. Examples
5. Resolution of the paradox "c + u´ = c"
6. Summary
1. Introduction

Fig. 1: Minkowski diagram of a uniformly moved rocket in space at a speed of v = 0.6 c, which shoots protons at the coordinate origin in the direction of the movement at a speed of u´= 0.65 c . In the referece system S of the observer the protons move on the red worldline.
2. The rotation angle
The angle φ depends on the velocity v or on v/c in this way:
cos φ = tan [ (π/4) - arctan (v/c) ] for 0 ≤ v ≤ c (1)

Fig. 2: Downside view (left) and side view (right) of the rotation of the angle δ out of the drawing level; ε is the orthogonal projection of the turned angle δ into the drawing level.
as well as tan δ = a
and tan ε = b .
So tan ε = a ∙ cos φ
and tan ε = tan δ ∙ cos φ . (2)
From the addition theorem of the tangent tan (x - y) = (tan x - tan y) / (1 + tan x ∙ tan y) follows from (1)
cos φ = (1 - v/c) / (1 + v/c) ,
cos φ = (c + v) / (c - v) for - c < v ≤ 0 see [2]
Now a second example is used to show that and how two relativistic velocities can be added by turning the rectangular coordinate system around the angle bisector w by the angle φ. For this the worldline of the second body (the proton, green in fig. 3) is drawn into the rectangular coordinate system. By the rotation by φ then the worldline of the second body in system S (red) results as the orthogonal projection of the turned (green) worldline of the second body.

Fig. 3: Minkowski-diagram for the relativistic addition of the velocities v = 0.2 c and u´ = 0.3 c ; The addition theorem of velocities results in u = 0.4717 c , the drawing in u = 5.1 Ls / 10.8 s = 0.472 c . (The rotation angle is φ = 48.19°, measurable in fig.7. With tan γ = u/c = 0.4717 follows γ = 25,25° , see below) .
3. Proof of the procedure
As c ≠ 0 applies u = (u´ + v) / (1 + u´v / c2) = [ (u´ + v) ∙ c2] / [ (1 + u´v/c2) ∙ c2] = [ (u´ + v) ∙ c2] / (c2 + u´ v) .
u ∙ (c2 + u´ v) = (u´ + v) ∙ c2 as (c2 + u´ v) ≠ 0 as per requirement | v | < c
(u c2 + u u´v) ∙ 2 = (u´c2 + v c2) ∙ 2
u c2 + u u´v + u c2 + u u´v = u´c2 + v c2 +u´c2 + v c2
On both sides is added +c3 - u v c - u u´c + u´v c .
c3 + u c2 - v c2 - u v c - u´c2 - u u´c + u´v c + u u´v = c3 + u´c2 + v c2 + u´v c - u c2 - u v c -u u´c - u u´v
(c - u´) ∙ (c2 + u c - v c - u v) = (c - u) ∙ (c2 + v c + u´c + u´v)
(c - u´) [ c (c + u) - v (c + u) ] = (c - u) [ c (c + v) +u´ (c + v) ]
(c - u´) (c - v) (c + u) = (c - u) (c + u´) (c + v)
Now on both sides is divided by [ (c + u´) (c + v) (c + u) ] . For this must apply u´, v, u ≠ - c . v ≠ - c is required above. Necessary at this point is the further restriction u´ ≠ - c . From v ≠ - c and u´ ≠ - c follows u ≠ - c too.
[ (c - u´) / (c + u´) ] ∙ [ (c - v) / (c + v) ] = [ (c - u) / (c + u) ] (5)
From 1 Ls = c ∙ 1 s follows v = s / t = (a Ls) / (b s) = (a / b) (c s / s) = (a / b) c (s. fig. 1) . It follows v / c = a / b
and from tan α = a / b follows
tan α = v / c and according fig. 3 tan γ =u / c , tan (45° - δ) = u´ / c . (6)
For the first fraction in (5) applies with (6)
[ (c - u´) / (c + u´) ] = [ (c - u´) (1 / c) ] / [ (c + u´) (1 / c) ] = [1 - (u´ / c) ] / [1 + (u´ / c) ]
= [1 - tan (45° - δ) ] / [1 + tan (45° + δ) ] = [1 - (1 - tan δ) / (1 + tan δ) ] / [1 + (1 - tan δ) / (1 + tan δ) ]
= { [1 + tan δ - (1 - tan δ) ] / [1 + tan δ ] } / { [1 + tan δ + 1 - tan δ] / [1 + tan δ] } = (2 tan δ) / 2 = tan δ .
For the second fraction in (5) applies (4) (c - v) / (c + v) = cos φ .
For the third fraction in (5) applies (c - u) / (c + u) = [ (c-u) 1/c ] / [ (c + u) 1/c ] = (1 - u / c) / (1 + u / c)
and with (6) = (1 - tan γ) / (1 + tan γ) = tan (45° - γ) .
From this follows for (5) tan δ ∙ cos φ = tan (45° - γ) . (7)
According fig. 3 applies 45°- γ = ε . So the angles δ and ε of fig. 3 fulfil equation 2 tan δ ∙ cos φ = tan ε
for the rotation of an angle δ around one of its legs which here is the angle bisector by an angle φ and with the orthogonal projection ε of angle δ on the initial surface. With this is shown that the relativistic addition of velocities can be done by the described procedure of the rotation of the rectangular reference system S´ into a fifth dimension as well for all | v | < c and all u´ with - c < u´ ≤ c .
4. Examples


The 5d-model is confirmed at a hardware-model, see the photographs in figures 5, 6, 8, 10 . Cameras do not produce parallel projections but central projections. That is why there are slight distortions and the right point of taking the pictures had to be chosen from a distance as large as possible. So the pictures had to be enlarged which caused fuzziness.

Fig. 5: Right-angled geo-triangle rotated by the angle φ at v = 0.2 c and u´ = 0.3 c . The dark worldline of the proton on the geo-triangle transitions differentiably into its red worldline in coordinate system S (the gap is caused by the flattened edge of the geo-triangle).


Fig. 7: The example of fig. 3 and 5, upside left side the spatial representation with the axes x, t and x5, the blue worldline for v = 0.2 c, the dotted green worldline for u´ = 0.3 c, the red worldline of the resulting velocity u = 0.4717 c, the turned black t-axis and the turned green worldline. Upside right the vertical projection shows that the blue worldline is the exact projection of the t´-axis and the covered red worldline is the exact projection of the turned green worldline for they are still visible at the upper ends. Downside left some calculated data concerning example 2 and downside right a side view with the measurably exact angle 48.2°.

Fig. 8: Comparison of the central projection (left side) and the parallel projection (right side) for v = 0.3 c and u´ = 0.8 c (u = 0.8871 c). The red worldline is covered by the green worldline. Comparable angles are equal in the left and right picture; they are independent of the scales. See also attachment fig. 10.
The resulting velocity u can also be calculated by means of analytic geometry using the blue lines g, d and e in fig. 3 [5]. And u can as well be calculated from the angles φ, α and β´ [5].
On the website https://www.youtube.com/watch?v=pd8bspQomdw a video with the measurement of the resulting velocity u is shown at a three-dimensional model using the fifth dimension.
5. Resolution of the paradox "c + u´ = c"

Fig. 9: Left side applies 0° ≤ φ < 90° , right side applies φ = 90° .
If φ = 90° the orthogonal projection of the green worldline of the second object coincides with the angle bisector w for any angle β´ (0 < β´ ≤ 45°). So the resulting velocity in S always is c. Paradoxically the first and the second object move together in S although the first object emits the second one. But in the fifth dimension they move away from each other at the speed u´ = (tan β´) ∙ c .
6. Summary
References
[2] R. Sprenger. Moving emitters and absorbers of photons. DOI10.5281/zenodo.10974861
[3] https://de.wikipedia.org/wiki/Drehmatrix
[4] John W. Eaton, David Bateman, Søren Hauberg, Rik Wehbring (2024).
[5] www.roland-sprenger.de. Relativistische Addition von Geschwindigkeiten im R5 . fig. 10 et seq.
[6] T. Kaluza: Zum Unitätsproblem der Physik. In: Sitzungsberichte Preußische Akademie der Wissenschaften. 1921. S. 966–972. archive.org.
[7] Klein, O. Quantentheorie und fünfdimensionale Relativitätstheorie. Z. Physik 37, 895–906 (1926).
https://doi.org/10.1007/BF01397481
[8] R. Sprenger. Universe without expansion and big bang. www.roland-sprenger.de
DOI 10.5281/zenodo.13336248
Attachment


GNU-Octave-program for the “Video_turning_to_plan.mp4”:
